{"id":188802,"date":"2024-10-11T15:10:56","date_gmt":"2024-10-11T18:10:56","guid":{"rendered":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/?post_type=eaja&#038;p=188802"},"modified":"2024-12-10T14:05:58","modified_gmt":"2024-12-10T17:05:58","slug":"matematica-explorando-o-volume-e-a-capacidade-dos-cilindros","status":"publish","type":"eaja","link":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/eaja\/matematica-explorando-o-volume-e-a-capacidade-dos-cilindros\/","title":{"rendered":"Matem\u00e1tica &#8211; Explorando o volume e a capacidade dos cilindros"},"content":{"rendered":"\n<p class=\"has-text-align-center has-medium-font-size\"><strong>Esta proposta de atividade de&nbsp;MATEM\u00c1TICA&nbsp;\u00e9 destinada aos estudantes do 5\u00ba per\u00edodo da Educa\u00e7\u00e3o de Jovens e Adultos \u2013 EJA<\/strong><\/p>\n\n\n\n<div class=\"wp-block-buttons is-content-justification-center is-layout-flex wp-container-core-buttons-is-layout-16018d1d wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=1Zkyvn4Mi7VZqxOLiFYS86GLrcDtqd82S\">BAIXE A ATIVIDADE<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=17xf2_WUhHePfThb0vuAx7xxwrqtK3DpN\">BAIXE OS SLIDES<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=1EN6rgnWcysOVtRUgnN38ZnxS0cXNcb3o\">BAIXE O TEXTO<\/a><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:15% auto\"><figure class=\"wp-block-media-text__media\"><img decoding=\"async\" width=\"152\" height=\"149\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/10\/cilindro.png\" alt=\"\" class=\"wp-image-188804 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-6257a0579face3991249bdef6610b045\" style=\"color:#060896\"><strong>Introdu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Neste texto, vamos aprender sobre o <strong>volume<\/strong> e a <strong>capacidade<\/strong> de objetos que t\u00eam a forma de cilindro reto. Definiremos volume e capacidade e como calcular, al\u00e9m de entender a rela\u00e7\u00e3o entre volume e capacidade com exemplos pr\u00e1ticos. No final, voc\u00ea encontrar\u00e1 dois problemas do dia a dia resolvidos.<\/p>\n\n\n\n<p class=\"has-small-font-size\">Imagem:<a href=\"http:\/\/canva.com\/cilindro\">canva.com\/cilindro<\/a>&nbsp;<\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-045b222c3741da8ce614155edca2a400\" style=\"color:#060896\"><strong>O Que \u00e9 Volume?<\/strong><\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-red-color has-text-color has-link-color has-medium-font-size wp-elements-19206e5d0ea1c4828284ffd936a5307e\"><strong>O volume \u00e9 a medida do espa\u00e7o ocupado por um objeto.&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">No caso dos cilindros, o volume depende do <strong>tamanho<\/strong> da <strong>base circular<\/strong> e da <strong>altura<\/strong> do cilindro. A base \u00e9 o c\u00edrculo na parte de baixo, e a altura \u00e9 a dist\u00e2ncia entre a base e o topo do cilindro.<\/p>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-57003a94b27fff6d6186352870d0ae37\" style=\"color:#060896\"><strong>As unidades de volume mais utilizadas s\u00e3o:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\">o m<sup>3<\/sup> ( metro c\u00fabico),&nbsp;<\/li>\n\n\n\n<li class=\"has-medium-font-size\">o dm<sup>3<\/sup> (dec\u00edmetro c\u00fabico) e&nbsp;<\/li>\n\n\n\n<li class=\"has-medium-font-size\">o cm<sup>3<\/sup> (cent\u00edmetro c\u00fabico).&nbsp;&nbsp;<\/li>\n<\/ul>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-3950e6ddd90da98fe41ebd6a53148bae\" style=\"color:#060896\"><strong>Como Calcular o Volume de um Cilindro?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Para calcular o volume de um cilindro reto, usamos a seguinte f\u00f3rmula:&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh7-rt.googleusercontent.com\/docsz\/AD_4nXd_KA31pDCtsafQSYhJqBMW002cDoh7eQk6cn0g0zYPnEgpmhTfdSDFEFf2ONGktemegxgWtu6-ykwPsoyKuRAHdTiRcknb2BaZ-yq4tvtxeLtX895ntMQZAE-psHfizZjohqsrmPikhNM_1gCrOi_wg5UQA5q5EYRif20B1Q?key=XjBKXHEx9mQSDOXnA5tKNw\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Onde, nesta f\u00f3rmula:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh7-rt.googleusercontent.com\/docsz\/AD_4nXfmw3eWNXv9cWtoVtJf-HxRGcZ-PXgS58Dout7oj9VMS2HQt6RQ-SPID_LDzNVA71aMCalFVaz3CP8zX45Gc2a8a1SYx8r9nnOQGR7cFxgUcJg93QAqD21UXN3OH8MpdV5iIp6buMh-lL80MK7PEEdLGaNeVkdnYo0SX_NGng?key=XjBKXHEx9mQSDOXnA5tKNw\" alt=\"\"\/><\/figure>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-4575e10bb8474bdd2e7c66efe26892de\" style=\"color:#060896\"><strong>O que \u00e9 Capacidade?<\/strong><\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-red-color has-text-color has-link-color has-medium-font-size wp-elements-e55d984a848df8e53984b89129b6a60d\"><strong>A Capacidade \u00e9 a quantidade de l\u00edquido que um objeto pode armazenar.<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">As unidades de capacidade mais utilizadas s\u00e3o:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\">o L (litro) e&nbsp;<\/li>\n\n\n\n<li class=\"has-medium-font-size\">o mL (mililitro).&nbsp;&nbsp;<\/li>\n<\/ul>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-b44d0562f05d116a3b4c8d4388479a8c\" style=\"color:#060896\"><strong>Rela\u00e7\u00e3o entre as unidades de medida de volume e capacidade<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\">1 m<sup>3<\/sup> = 1000 L<\/li>\n\n\n\n<li class=\"has-medium-font-size\">1 cm<sup>3<\/sup> = 1 mL<\/li>\n\n\n\n<li class=\"has-medium-font-size\">1 dm<sup>3<\/sup> = 1 L<\/li>\n<\/ul>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-faa765268aee3bc55e0fcc4a308b292c\" style=\"color:#060896\"><strong>Problemas do Cotidiano<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Problema 1: Caixa d\u2019\u00e1gua cil\u00edndrica<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Uma caixa d\u2019\u00e1gua em forma de cilindro tem um raio de 50 cm e uma altura de 100 cm. Qual \u00e9 o volume de \u00e1gua que essa caixa pode armazenar?<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Resolu\u00e7\u00e3o:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Usamos a f\u00f3rmula do volume de um cilindro:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh7-rt.googleusercontent.com\/docsz\/AD_4nXd_KA31pDCtsafQSYhJqBMW002cDoh7eQk6cn0g0zYPnEgpmhTfdSDFEFf2ONGktemegxgWtu6-ykwPsoyKuRAHdTiRcknb2BaZ-yq4tvtxeLtX895ntMQZAE-psHfizZjohqsrmPikhNM_1gCrOi_wg5UQA5q5EYRif20B1Q?key=XjBKXHEx9mQSDOXnA5tKNw\" alt=\"\" style=\"width:153px;height:auto\"\/><\/figure><\/div>\n\n\n<p class=\"has-medium-font-size\">V = 3,14 . 50<sup>2<\/sup> . 100 = 3,14 . 2500 . 100 = 7850 . 100 = 785000 cm<sup>3<\/sup>.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Resposta:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Como 1 litro \u00e9 igual a 1000 cm\u00b3, o volume da caixa d&#8217;\u00e1gua \u00e9 de 785 litros (785000:1000).<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Problema 2: Copo de pl\u00e1stico<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Um copo descart\u00e1vel tem 4 cm de raio na base e 10 cm de altura. Qual \u00e9 a capacidade m\u00e1xima de l\u00edquido que esse copo pode conter?<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Resolu\u00e7\u00e3o: Usamos a f\u00f3rmula do volume:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh7-rt.googleusercontent.com\/docsz\/AD_4nXd_KA31pDCtsafQSYhJqBMW002cDoh7eQk6cn0g0zYPnEgpmhTfdSDFEFf2ONGktemegxgWtu6-ykwPsoyKuRAHdTiRcknb2BaZ-yq4tvtxeLtX895ntMQZAE-psHfizZjohqsrmPikhNM_1gCrOi_wg5UQA5q5EYRif20B1Q?key=XjBKXHEx9mQSDOXnA5tKNw\" alt=\"\" style=\"width:144px;height:auto\"\/><\/figure><\/div>\n\n\n<p class=\"has-medium-font-size\">V = 3,14 . 4<sup>3<\/sup> . 10 = 3,14 . 16 . 10 = 50,24 . 10 = 502,4 cm<sup>3<\/sup>.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Resposta:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Como 1 cm<sup>3<\/sup> \u00e9 igual a 1 mL, o copo pode conter 502,4 mL, ou seja, aproximadamente 0,502 litros, o que \u00e9 um pouco a mais do que meio litro de l\u00edquido.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Ficamos por aqui, at\u00e9 o pr\u00f3ximo.<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Atividade<\/strong><\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 01<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Uma lata de \u00f3leo tem a forma de um cilindro.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">A) Se a lata tem 10 cm de altura e o raio da base mede 5 cm, qual \u00e9 o volume de \u00f3leo que ela pode conter?<\/p>\n\n\n\n<p class=\"has-medium-font-size\">B) Se cada mililitro de \u00f3leo corresponde a 1 cm\u00b3 de volume, quantos mililitros de \u00f3leo cabem na lata?<\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 02<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Um tanque de combust\u00edvel de um carro tem a forma de um cilindro.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">A) Se o tanque tem 50 cm de comprimento e o raio da base mede 20 cm, qual \u00e9 a capacidade do tanque em litros? (Considere que 1 dm\u00b3 equivale a 1 litro.)<\/p>\n\n\n\n<p class=\"has-medium-font-size\">B) Se o tanque est\u00e1 com metade da sua capacidade, quantos litros de combust\u00edvel faltam para ench\u00ea-lo?<\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 03<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Um tanque de \u00e1gua em formato cil\u00edndrico tem 2 metros de altura e raio da base de 1,5 metros. A capacidade desse tanque, em litros, \u00e9&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(A) 14130 litros.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(B) 7065 litros.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(C) 3532,5 litros.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(D) 2826 litros.<\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 04<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Uma vela em formato de cilindro tem 12 cm de altura e raio da base de 2 cm. Se a vela queima completamente a uma taxa de 2 cm\u00b3 por hora, o tempo aproximado que a vela levar\u00e1 para se consumir completamente \u00e9 de&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(A) 150 horas.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(B) 75 horas.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(C) 30 horas.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(D) 15 horas.<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-cyan-blue-background-color has-text-color has-background has-link-color has-medium-font-size wp-elements-d853bf25a9f02e7c007dfb46f9294b96\"><strong>SAIBA MAIS<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Assista ao v\u00eddeo para aprender um pouco mais sobre Volume e Capacidade<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<p class=\"responsive-video-wrap clr\"><iframe title=\"Volume de Cilindro _ Lata de Extrato de Tomate\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/f2WsnwHSf4U?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe><\/p>\n<\/div><\/figure>\n\n\n\n<figure class=\"wp-block-table is-style-stripes\"><table><tbody><tr><td>Autoria<\/td><td>Professor H\u00e9lio Roberto da Rocha, Mestre em Matem\u00e1tica.<\/td><\/tr><tr><td>Componente Curricular<\/td><td>Matem\u00e1tica<\/td><\/tr><tr><td>Objetivos de aprendizagem e desenvolvimento<\/td><td>(EJAMA0527) Interpretar, resolver e elaborar situa\u00e7\u00f5es-problema que envolvam o c\u00e1lculo do volume de recipientes cujo formato \u00e9 de bloco retangular ou de cilindro reto.<\/td><\/tr><tr><td>Refer\u00eancias<\/td><td>SOUZA, Joamir Roberto de: Matem\u00e1tica realidade &amp; tecnologia: 6\u00ba ao 9\u00ba ano: ensino fundamental: anos finais \/ Joamir Roberto de Souza. \u2013 1. ed. \u2013 S\u00e3o Paulo: FTD, 2018.<br>GIOVANNI J\u00daNIOR, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 6\u00ba ao 9\u00ba ano: ensino fundamental: anos finais \/ Jos\u00e9 Ruy Giovanni J\u00fanior, Benedicto Castrucci. \u2014 4. ed. \u2014 S\u00e3o Paulo: FTD, 2018.<br>GOI\u00c2NIA. Secretaria Municipal de Educa\u00e7\u00e3o. Aprender Sempre. 6\u00ba ao 9\u00b0 ano &#8211; Ensino Fundamental; Matem\u00e1tica; Goi\u00e2nia, 2024.<\/td><\/tr><\/tbody><\/table><\/figure>\n","protected":false},"author":47,"featured_media":188805,"template":"","meta":{"_acf_changed":false,"ocean_post_layout":"","ocean_both_sidebars_style":"","ocean_both_sidebars_content_width":0,"ocean_both_sidebars_sidebars_width":0,"ocean_sidebar":"","ocean_second_sidebar":"","ocean_disable_margins":"enable","ocean_add_body_class":"","ocean_shortcode_before_top_bar":"","ocean_shortcode_after_top_bar":"","ocean_shortcode_before_header":"","ocean_shortcode_after_header":"","ocean_has_shortcode":"","ocean_shortcode_after_title":"","ocean_shortcode_before_footer_widgets":"","ocean_shortcode_after_footer_widgets":"","ocean_shortcode_before_footer_bottom":"","ocean_shortcode_after_footer_bottom":"","ocean_display_top_bar":"default","ocean_display_header":"default","ocean_header_style":"","ocean_center_header_left_menu":"","ocean_custom_header_template":"","ocean_custom_logo":0,"ocean_custom_retina_logo":0,"ocean_custom_logo_max_width":0,"ocean_custom_logo_tablet_max_width":0,"ocean_custom_logo_mobile_max_width":0,"ocean_custom_logo_max_height":0,"ocean_custom_logo_tablet_max_height":0,"ocean_custom_logo_mobile_max_height":0,"ocean_header_custom_menu":"","ocean_menu_typo_font_family":"","ocean_menu_typo_font_subset":"","ocean_menu_typo_font_size":0,"ocean_menu_typo_font_size_tablet":0,"ocean_menu_typo_font_size_mobile":0,"ocean_menu_typo_font_size_unit":"px","ocean_menu_typo_font_weight":"","ocean_menu_typo_font_weight_tablet":"","ocean_menu_typo_font_weight_mobile":"","ocean_menu_typo_transform":"","ocean_menu_typo_transform_tablet":"","ocean_menu_typo_transform_mobile":"","ocean_menu_typo_line_height":0,"ocean_menu_typo_line_height_tablet":0,"ocean_menu_typo_line_height_mobile":0,"ocean_menu_typo_line_height_unit":"","ocean_menu_typo_spacing":0,"ocean_menu_typo_spacing_tablet":0,"ocean_menu_typo_spacing_mobile":0,"ocean_menu_typo_spacing_unit":"","ocean_menu_link_color":"","ocean_menu_link_color_hover":"","ocean_menu_link_color_active":"","ocean_menu_link_background":"","ocean_menu_link_hover_background":"","ocean_menu_link_active_background":"","ocean_menu_social_links_bg":"","ocean_menu_social_hover_links_bg":"","ocean_menu_social_links_color":"","ocean_menu_social_hover_links_color":"","ocean_disable_title":"default","ocean_disable_heading":"default","ocean_post_title":"","ocean_post_subheading":"","ocean_post_title_style":"","ocean_post_title_background_color":"","ocean_post_title_background":0,"ocean_post_title_bg_image_position":"","ocean_post_title_bg_image_attachment":"","ocean_post_title_bg_image_repeat":"","ocean_post_title_bg_image_size":"","ocean_post_title_height":0,"ocean_post_title_bg_overlay":0.5,"ocean_post_title_bg_overlay_color":"","ocean_disable_breadcrumbs":"default","ocean_breadcrumbs_color":"","ocean_breadcrumbs_separator_color":"","ocean_breadcrumbs_links_color":"","ocean_breadcrumbs_links_hover_color":"","ocean_display_footer_widgets":"default","ocean_display_footer_bottom":"default","ocean_custom_footer_template":""},"eaja_categoria":[69],"serie":[76],"eaja_componente":[78],"class_list":["post-188802","eaja","type-eaja","status-publish","has-post-thumbnail","hentry","eaja_categoria-2o-segmento-7a-e-8a-serie","serie-7a-serie","eaja_componente-matematica","entry","has-media"],"acf":[],"_links":{"self":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja\/188802","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja"}],"about":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/types\/eaja"}],"author":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/users\/47"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media\/188805"}],"wp:attachment":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media?parent=188802"}],"wp:term":[{"taxonomy":"eaja_categoria","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_categoria?post=188802"},{"taxonomy":"serie","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/serie?post=188802"},{"taxonomy":"eaja_componente","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_componente?post=188802"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}