{"id":180822,"date":"2024-04-11T16:17:55","date_gmt":"2024-04-11T19:17:55","guid":{"rendered":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/?post_type=eaja&#038;p=180822"},"modified":"2024-05-22T13:29:12","modified_gmt":"2024-05-22T16:29:12","slug":"matematica-resolvendo-problemas-de-area-do-circulo","status":"publish","type":"eaja","link":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/eaja\/matematica-resolvendo-problemas-de-area-do-circulo\/","title":{"rendered":"Matem\u00e1tica &#8211; Resolvendo Problemas de \u00c1rea do C\u00edrculo"},"content":{"rendered":"\n<p class=\"has-text-align-center has-medium-font-size\"><strong>Esta proposta de atividade de Matem\u00e1tica \u00e9 destinada aos estudantes do 6\u00ba Per\u00edodo (8\u00aa s\u00e9rie)&nbsp;da Educa\u00e7\u00e3o de Jovens e Adultos \u2013 EJA.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-buttons is-content-justification-center is-layout-flex wp-container-core-buttons-is-layout-16018d1d wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=18ksFQM5j61JyDSkuaEl8W8I3IU9kdrNI\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE A ATIVIDADE<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=1B1i00Z4WzAtvkiGcllmm5FcAM57G0m82\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE OS SLIDES<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=194ZFJpqUEb2wrd4tKJD8pdSjUIDnYxvc\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE O TEXTO<\/a><\/div>\n<\/div>\n\n\n\n<p><\/p>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:22% auto\"><figure class=\"wp-block-media-text__media\"><img decoding=\"async\" width=\"207\" height=\"185\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/circulo.png\" alt=\"\" class=\"wp-image-180824 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-674d82a1a282507650baf7a07e94e464\" style=\"color:#1f9714\"><strong>Introdu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">O c\u00edrculo \u00e9 uma figura geom\u00e9trica simples, mas muito presente em nosso dia a dia, sendo encontrada em objetos como moedas, bot\u00f5es e CDs. Neste texto iremos apresentar sua defini\u00e7\u00e3o, seus elementos e como calcular a medida da sua \u00e1rea, al\u00e9m de 2 problemas resolvidos.<\/p>\n\n\n\n<p>Imagem: canva.com\/<a href=\"https:\/\/l1nk.dev\/rTmQD\">https:\/\/l1nk.dev\/rTmQD<\/a><\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-43d5d8217c9c5feaf3154956c12e010c\" style=\"color:#1f9714\"><strong>Defini\u00e7\u00e3o e Elementos de um C\u00edrculo<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Um c\u00edrculo \u00e9 a regi\u00e3o plana <strong>limitada por uma circunfer\u00eancia<\/strong>. Ele possui um raio, que \u00e9 a dist\u00e2ncia do centro do c\u00edrculo at\u00e9 qualquer ponto da sua circunfer\u00eancia.<\/p>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-0bfdc45698d6d7a0d748c86d902fc419\" style=\"color:#1f9714\"><strong>Seus principais elementos s\u00e3o:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\"><strong>Centro:<\/strong> ponto dentro do c\u00edrculo de onde todas as dist\u00e2ncias at\u00e9 a circunfer\u00eancia s\u00e3o iguais.<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Circunfer\u00eancia:<\/strong> linha curva que delimita o c\u00edrculo.<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Raio:<\/strong> segmento de reta que une o centro do c\u00edrculo a um ponto qualquer da circunfer\u00eancia.<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Di\u00e2metro:<\/strong> segmento de reta que passa pelo centro do c\u00edrculo e tem suas extremidades na circunfer\u00eancia. \u00c9 o dobro do raio.<\/li>\n<\/ul>\n\n\n\n<p class=\"has-medium-font-size\">Veja na imagem esses elementos<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img fetchpriority=\"high\" decoding=\"async\" width=\"414\" height=\"210\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-35.png\" alt=\"\" class=\"wp-image-180828\" style=\"width:249px;height:auto\" srcset=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-35.png 414w, https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-35-300x152.png 300w\" sizes=\"(max-width: 414px) 100vw, 414px\" \/><\/figure><\/div>\n\n\n<p class=\"has-text-align-center has-small-font-size\">Imagem do Autor produzida no Geogebra<\/p>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-eefa2cdca76ab90119c90aa4bf357b6a\" style=\"color:#1f9714\"><strong>\u00c1rea do C\u00edrculo<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">A \u00e1rea do c\u00edrculo \u00e9 a medida da sua regi\u00e3o interna. Para calcular a \u00e1rea de um c\u00edrculo, utilizamos a f\u00f3rmula:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" width=\"109\" height=\"24\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-36.png\" alt=\"\" class=\"wp-image-180829\" style=\"width:127px;height:auto\"\/><\/figure><\/div>\n\n\n<p class=\"has-medium-font-size\">Onde:&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"308\" height=\"53\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-37.png\" alt=\"\" class=\"wp-image-180830\" srcset=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-37.png 308w, https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-37-300x52.png 300w\" sizes=\"(max-width: 308px) 100vw, 308px\" \/><\/figure>\n\n\n\n<p class=\"has-text-color has-link-color has-medium-font-size wp-elements-b8f443a3f0943a5ccad3a44a163fa9dd\" style=\"color:#1f9714\"><strong>Problemas de Aplica\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Problema 1<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Alice tem um espelho circular, como o da figura abaixo, onde a parte espelhada possui 40cm de di\u00e2metro. Ela decidiu decorar a moldura do espelho com adesivos decorativos, mas quer ter certeza de que n\u00e3o cobrir\u00e1 a \u00e1rea \u00fatil do espelho. Qual \u00e9 a \u00e1rea da superf\u00edcie do espelho que Alice pode usar para se ver refletida?<\/p>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:23% auto\"><figure class=\"wp-block-media-text__media\"><img loading=\"lazy\" decoding=\"async\" width=\"223\" height=\"165\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/espelho.png\" alt=\"\" class=\"wp-image-180826 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-medium-font-size\"><strong>Resolu\u00e7\u00e3o:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Aplicando a f\u00f3rmula que calcula a medida da \u00e1rea e considerando o valor do pi aproximadamente igual a 3,14, teremos:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"396\" height=\"24\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-38.png\" alt=\"\" class=\"wp-image-180831\" style=\"width:423px;height:auto\" srcset=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-38.png 396w, https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-38-300x18.png 300w\" sizes=\"(max-width: 396px) 100vw, 396px\" \/><\/figure>\n\n\n\n<p class=\"has-small-font-size\">Imagem: canva.com\/<a href=\"https:\/\/l1nk.dev\/rTmQD\">https:\/\/l1nk.dev\/rTmQD<\/a><\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-medium-font-size\">Lembrando que a medida do raio \u00e9 igual \u00e0 metade da medida do di\u00e2metro.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Resposta:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">A medida da \u00e1rea da superf\u00edcie do espelho que Alice pode usar \u00e9 de 1256 cm<sup>2<\/sup> .<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Problema 2<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Jo\u00e3o possui um jardim com canteiros circulares de raio 3 metros. Ele deseja comprar adubo para cobrir a \u00e1rea de todos os canteiros. Sabendo que cada metro quadrado requer 1 kg de adubo, quantos quilogramas de adubo Jo\u00e3o deve comprar?<\/p>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:23% auto\"><figure class=\"wp-block-media-text__media\"><img loading=\"lazy\" decoding=\"async\" width=\"218\" height=\"126\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/jardim.png\" alt=\"\" class=\"wp-image-180827 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-medium-font-size\"><strong>Resolu\u00e7\u00e3o:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Aplicando a f\u00f3rmula que calcula a medida da \u00e1rea e considerando o valor do pi aproximadamente igual a 3,14, teremos:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"359\" height=\"28\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-39.png\" alt=\"\" class=\"wp-image-180832\" srcset=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-39.png 359w, https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2024\/04\/image-39-300x23.png 300w\" sizes=\"(max-width: 359px) 100vw, 359px\" \/><\/figure>\n\n\n\n<p class=\"has-small-font-size\">Imagem: canva.com\/<a href=\"https:\/\/l1nk.dev\/rTmQD\">https:\/\/l1nk.dev\/rTmQD<\/a><\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Resposta:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Como cada metro quadrado requer 1 kg de adubo, Jo\u00e3o deve comprar 28,26 kg de adubo.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Para finalizar, quero deixar aqui registrado a import\u00e2ncia de se conhecer a f\u00f3rmula da \u00e1rea de regi\u00f5es circulares, pois permite resolver diversas situa\u00e7\u00f5es que nos deparamos no nosso dia-a-dia que envolva objetos circulares.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Ficamos por aqui, at\u00e9 o pr\u00f3ximo.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>OBS.<\/strong> Em todas as quest\u00f5es, utilizar o valor do pi igual a 3.<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 01<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Maria tem um jardim circular com raio de 5 metros. Ela deseja colocar um c\u00edrculo de pedras decorativas ao redor das rosas, com um raio de 7 metros. Quantos metros quadrados de pedras ela precisa para completar o c\u00edrculo externo?<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 02<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Uma medalha ol\u00edmpica tem a forma de um c\u00edrculo com di\u00e2metro de 5 cent\u00edmetros. Qual \u00e9 a \u00e1rea da medalha?<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 03<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Uma horta circular tem um raio de 6 metros. Se voc\u00ea deseja colocar esterco na horta voc\u00ea ir\u00e1 precisar de<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(A) 78 metros quadrados.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(B) 88 metros quadrados.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(C) 108 metros quadrados.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(D) 110 metros quadrados.<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 04<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">A \u00e1rea de um espelho circular de 60 cent\u00edmetros de di\u00e2metro \u00e9 igual a&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(A) 2500 cm\u00b2.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(B) 2600 cm\u00b2.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(C) 2650 cm\u00b2.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(D) 2700 cm\u00b2.<\/p>\n\n\n\n<p class=\"has-black-color has-vivid-green-cyan-background-color has-text-color has-background has-link-color has-medium-font-size wp-elements-c37237873c998ed377b85b5095f79bf6\"><strong>SAIBA MAIS<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Aprenda um pouco mais sobre comprimento e \u00e1rea de c\u00edrculo.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\nhttps:\/\/www.youtube.com\/watch?v=BY2zn4dzY_k&#038;t=112s\n<\/div><figcaption class=\"wp-element-caption\">Canal do Professor H\u00e9lio &lt;YouTube&gt;<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-table is-style-stripes\"><table><tbody><tr><td>Autoria<\/td><td>Professor H\u00e9lio Roberto da Rocha, Mestre em matem\u00e1tica<\/td><\/tr><tr><td>Componente curricular<\/td><td>Matem\u00e1tica<\/td><\/tr><tr><td>Objetivos de aprendizagem e desenvolvimento<\/td><td>(EJAMA0617) Resolver situa\u00e7\u00f5es-problema envolvendo o c\u00e1lculo das medidas do comprimento da circunfer\u00eancia e \u00e1rea do c\u00edrculo.<\/td><\/tr><tr><td>Refer\u00eancias<\/td><td>SOUZA, Joamir Roberto de: Matem\u00e1tica realidade &amp; tecnologia: 9\u00ba ano: ensino fundamental: anos finais \/Joamir Roberto de Souza. \u2013 1. ed. \u2013 S\u00e3o Paulo: FTD, 2018.<br>GIOVANNI J\u00daNIOR, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 9\u00b0 ano: ensino fundamental: anos finais \/ Jos\u00e9 Ruy Giovanni J\u00fanior, Benedicto Castrucci. \u2014 4. ed. \u2014 S\u00e3o Paulo: FTD, 2018.<br>GOI\u00c2NIA. Secretaria Municipal de Educa\u00e7\u00e3o. Aprender Sempre. 6\u00ba ao 9\u00ba ano &#8211; Ensino Fundamental; Matem\u00e1tica; Goi\u00e2nia, 2024.<br><\/td><\/tr><\/tbody><\/table><\/figure>\n","protected":false},"author":47,"featured_media":180824,"template":"","meta":{"_acf_changed":false,"ocean_post_layout":"","ocean_both_sidebars_style":"","ocean_both_sidebars_content_width":0,"ocean_both_sidebars_sidebars_width":0,"ocean_sidebar":"","ocean_second_sidebar":"","ocean_disable_margins":"enable","ocean_add_body_class":"","ocean_shortcode_before_top_bar":"","ocean_shortcode_after_top_bar":"","ocean_shortcode_before_header":"","ocean_shortcode_after_header":"","ocean_has_shortcode":"","ocean_shortcode_after_title":"","ocean_shortcode_before_footer_widgets":"","ocean_shortcode_after_footer_widgets":"","ocean_shortcode_before_footer_bottom":"","ocean_shortcode_after_footer_bottom":"","ocean_display_top_bar":"default","ocean_display_header":"default","ocean_header_style":"","ocean_center_header_left_menu":"","ocean_custom_header_template":"","ocean_custom_logo":0,"ocean_custom_retina_logo":0,"ocean_custom_logo_max_width":0,"ocean_custom_logo_tablet_max_width":0,"ocean_custom_logo_mobile_max_width":0,"ocean_custom_logo_max_height":0,"ocean_custom_logo_tablet_max_height":0,"ocean_custom_logo_mobile_max_height":0,"ocean_header_custom_menu":"","ocean_menu_typo_font_family":"","ocean_menu_typo_font_subset":"","ocean_menu_typo_font_size":0,"ocean_menu_typo_font_size_tablet":0,"ocean_menu_typo_font_size_mobile":0,"ocean_menu_typo_font_size_unit":"px","ocean_menu_typo_font_weight":"","ocean_menu_typo_font_weight_tablet":"","ocean_menu_typo_font_weight_mobile":"","ocean_menu_typo_transform":"","ocean_menu_typo_transform_tablet":"","ocean_menu_typo_transform_mobile":"","ocean_menu_typo_line_height":0,"ocean_menu_typo_line_height_tablet":0,"ocean_menu_typo_line_height_mobile":0,"ocean_menu_typo_line_height_unit":"","ocean_menu_typo_spacing":0,"ocean_menu_typo_spacing_tablet":0,"ocean_menu_typo_spacing_mobile":0,"ocean_menu_typo_spacing_unit":"","ocean_menu_link_color":"","ocean_menu_link_color_hover":"","ocean_menu_link_color_active":"","ocean_menu_link_background":"","ocean_menu_link_hover_background":"","ocean_menu_link_active_background":"","ocean_menu_social_links_bg":"","ocean_menu_social_hover_links_bg":"","ocean_menu_social_links_color":"","ocean_menu_social_hover_links_color":"","ocean_disable_title":"default","ocean_disable_heading":"default","ocean_post_title":"","ocean_post_subheading":"","ocean_post_title_style":"","ocean_post_title_background_color":"","ocean_post_title_background":0,"ocean_post_title_bg_image_position":"","ocean_post_title_bg_image_attachment":"","ocean_post_title_bg_image_repeat":"","ocean_post_title_bg_image_size":"","ocean_post_title_height":0,"ocean_post_title_bg_overlay":0.5,"ocean_post_title_bg_overlay_color":"","ocean_disable_breadcrumbs":"default","ocean_breadcrumbs_color":"","ocean_breadcrumbs_separator_color":"","ocean_breadcrumbs_links_color":"","ocean_breadcrumbs_links_hover_color":"","ocean_display_footer_widgets":"default","ocean_display_footer_bottom":"default","ocean_custom_footer_template":""},"eaja_categoria":[69],"serie":[100],"eaja_componente":[78],"class_list":["post-180822","eaja","type-eaja","status-publish","has-post-thumbnail","hentry","eaja_categoria-2o-segmento-7a-e-8a-serie","serie-8a-serie","eaja_componente-matematica","entry","has-media"],"acf":[],"_links":{"self":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja\/180822","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja"}],"about":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/types\/eaja"}],"author":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/users\/47"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media\/180824"}],"wp:attachment":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media?parent=180822"}],"wp:term":[{"taxonomy":"eaja_categoria","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_categoria?post=180822"},{"taxonomy":"serie","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/serie?post=180822"},{"taxonomy":"eaja_componente","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_componente?post=180822"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}