{"id":173347,"date":"2023-11-24T14:05:45","date_gmt":"2023-11-24T17:05:45","guid":{"rendered":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/?post_type=eaja&#038;p=173347"},"modified":"2024-03-29T18:51:58","modified_gmt":"2024-03-29T21:51:58","slug":"matematica-explorando-as-relacoes-metricas-no-triangulo-retangulo","status":"publish","type":"eaja","link":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/eaja\/matematica-explorando-as-relacoes-metricas-no-triangulo-retangulo\/","title":{"rendered":"Matem\u00e1tica &#8211; Explorando as rela\u00e7\u00f5es m\u00e9tricas no tri\u00e2ngulo ret\u00e2ngulo"},"content":{"rendered":"\n<p class=\"has-text-align-center has-medium-font-size\"><strong>Esta proposta de atividade de Matem\u00e1tica \u00e9 destinada aos estudantes do 6\u00ba Per\u00edodo (8\u00aa s\u00e9rie)&nbsp;da Educa\u00e7\u00e3o de Jovens e Adultos \u2013 EJA.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-buttons has-custom-font-size has-small-font-size is-content-justification-center is-layout-flex wp-container-core-buttons-is-layout-16018d1d wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button has-custom-font-size has-medium-font-size\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=1Vrtsmz80UjTbuvU-zeAPYxdpC26ubOuy\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE A ATIVIDADE<\/a><\/div>\n\n\n\n<div class=\"wp-block-button has-custom-font-size has-medium-font-size\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=1cSLfmWnTqMJfHf2t8aR-hGpOTzlA186Z\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE OS SLIDES<\/a><\/div>\n\n\n\n<div class=\"wp-block-button has-custom-font-size has-medium-font-size\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=18Y_vMVGgcFD5FD2TarINiNsp-kRHFltk\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE O TEXTO<\/a><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:21% auto\"><figure class=\"wp-block-media-text__media\"><img decoding=\"async\" width=\"229\" height=\"117\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/11\/pp3.png\" alt=\"\" class=\"wp-image-173350 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#128018\"><strong>Quem \u00e9 o tri\u00e2ngulo ret\u00e2ngulo?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">O tri\u00e2ngulo ret\u00e2ngulo \u00e9 um tipo de tri\u00e2ngulo que possui um \u00e2ngulo interno reto (90\u00b0) no qual a <strong>hipotenusa<\/strong> \u00e9 o lado oposto ao \u00e2ngulo reto (maior lado), enquanto os outros dois lados s\u00e3o conhecidos como <strong>catetos<\/strong>.<\/p>\n\n\n\n<p class=\"has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#128018\"><strong>O que s\u00e3o rela\u00e7\u00f5es m\u00e9tricas no tri\u00e2ngulo ret\u00e2ngulo?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">As rela\u00e7\u00f5es m\u00e9tricas <strong>s\u00e3o f\u00f3rmulas<\/strong> que relacionam as medidas dos <strong>comprimentos dos lados<\/strong> de uma figura. S\u00e3o, na maioria das vezes, utilizadas para resolver problemas sobre medidas de <strong>comprimentos de lados<\/strong>, <strong>altura<\/strong> e <strong>proje\u00e7\u00f5es<\/strong> de um tri\u00e2ngulo ret\u00e2ngulo.<\/p>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#128018\"><strong>Elementos de um tri\u00e2ngulo ret\u00e2ngulo<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Considere o <strong>tri\u00e2ngulo ret\u00e2ngulo RST<\/strong>, nele destacamos alguns elementos principais que se utilizam das rela\u00e7\u00f5es m\u00e9tricas para determinar suas medidas:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/8UFxbknKg7W76xpPZDDoy-5aUfUhhHpr09ZP7-zSpar3HHUeI4MfwU8zutTr-8AI7fx_4htFqY_ESAB3SstrwZ2Fr3tVZXR1TffNoDwFZMblaSKGmAyiz23OPPvg0E6bIlg9BEAgymH9\" alt=\"\" style=\"width:214px;height:131px\"\/><\/figure><\/div>\n\n\n<p class=\"has-text-align-center has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\"><strong>Hipotenusa (a)<\/strong>: \u00e9 o lado oposto ao \u00e2ngulo reto.<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Catetos (b e c)<\/strong>: s\u00e3o os dois lados que formam o \u00e2ngulo reto.<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Altura (h)<\/strong>: \u00e9 a altura do tri\u00e2ngulo ret\u00e2ngulo RST.<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Proje\u00e7\u00f5es (m e n)<\/strong>: s\u00e3o as proje\u00e7\u00f5es ortogonais dos catetos RS e RT.<\/li>\n<\/ul>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#128018\"><strong>Quais as principais rela\u00e7\u00f5es m\u00e9tricas de um tri\u00e2ngulo ret\u00e2ngulo?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">As principais s\u00e3o:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\"><strong>Teorema de Pit\u00e1goras:<\/strong> o quadrado da hipotenusa \u00e9 igual a soma dos quadrados dos catetos. ( <strong>a<sup>2<\/sup> = b<sup>2<\/sup> + c<sup>2<\/sup><\/strong> ).<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Rela\u00e7\u00e3o altura\/proje\u00e7\u00f5es:<\/strong> o quadrado da altura \u00e9 igual ao produto das proje\u00e7\u00f5es       ( <strong>h<\/strong><strong><sup>2<\/sup> <\/strong><strong>= m.n <\/strong>).<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Rela\u00e7\u00e3o cateto\/hipotenusa\/proje\u00e7\u00e3o:<\/strong> o quadrado do cateto \u00e9 igual ao produto da hipotenusa pela sua proje\u00e7\u00e3o ortogonal (<strong>c<\/strong><strong><sup>2<\/sup><\/strong><strong> = a.m <\/strong>e <strong>b<\/strong><strong><sup>2<\/sup><\/strong><strong> = a.n<\/strong>)<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>Rela\u00e7\u00e3o cateto\/cateto\/hipotenusa\/altura:<\/strong> o produto dos catetos \u00e9 igual ao produto da hipotenusa pela altura do tri\u00e2ngulo (<strong>b.c = a.h<\/strong>).<\/li>\n<\/ul>\n\n\n\n<p class=\"has-medium-font-size\">Em resumo:<\/p>\n\n\n\n<p class=\"has-text-align-center has-medium-font-size\"><strong>a<\/strong><strong><sup>2<\/sup><\/strong><strong> = b<\/strong><strong><sup>2<\/sup><\/strong><strong> + c<\/strong><strong><sup>2<\/sup><\/strong><strong>&nbsp; &nbsp; &nbsp; h<\/strong><strong><sup>2<\/sup><\/strong><strong> = m.n<\/strong><strong> &nbsp; &nbsp; <\/strong><strong>c<\/strong><strong><sup>2<\/sup><\/strong><strong> = a.m &nbsp; &nbsp; b<\/strong><strong><sup>2<\/sup><\/strong><strong> = a.n &nbsp; &nbsp; b.c = a.h<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Essas rela\u00e7\u00f5es podem ser comprovadas por <strong>semelhan\u00e7a de tri\u00e2ngulos<\/strong>, acesse o link abaixo que voc\u00ea poder\u00e1 relembrar um pouco desse assunto.<\/p>\n\n\n\n<p class=\"has-small-font-size\">Link: <a href=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/eaja\/matematica-semelhanca-de-triangulos\/\">Matem\u00e1tica \u2013 A semelhan\u00e7a de tri\u00e2ngulos no c\u00e1lculo de alturas \u2013 Conex\u00e3o Escola SME (goiania.go.gov.br)<\/a><\/p>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#128018\"><strong>Dois problemas para fixar esse assunto<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Problema 1:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Determinar a medida da altura do tri\u00e2ngulo ret\u00e2ngulo PQS abaixo:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/r6z7UC_5hTd1xN7bOy9eac3eeTSEiHhfoZ-cUqGTf9sME-CIBXj6oH_ofgjrV-l0VPLCwuEjHvtirsCyiKI7KxWhaAKzDtx1zm8y2oNIz4-chfq5CcyEJlyurYvb8YeVXQSCfKTnmAih\" alt=\"\" style=\"width:217px;height:110px\"\/><\/figure><\/div>\n\n\n<p class=\"has-text-align-center has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Solu\u00e7\u00e3o:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Aplicando a rela\u00e7\u00e3o altura\/proje\u00e7\u00f5es, teremos:<\/p>\n\n\n\n<p class=\"has-medium-font-size\">h<sup>2<\/sup> = m.n ( Substituindo os valores: m = 4 e n = 9)<\/p>\n\n\n\n<p class=\"has-medium-font-size\">h<sup>2<\/sup> = 4.9<\/p>\n\n\n\n<p class=\"has-medium-font-size\">h<sup>2<\/sup> = 36 (Extraindo a raiz quadrada)<\/p>\n\n\n\n<p class=\"has-medium-font-size\">h = 6<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Resposta: A medida da altura do tri\u00e2ngulo PQS \u00e9 igual a 6 unidades.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Problema 2<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Determinar as medidas dos catetos do tri\u00e2ngulo XYZ abaixo:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/WJJF4JuPIpcdB3cktykCnwmMaNqbGxAwxDOq-WSay7aRsrvuxUC9k3ds-BI9wnQnlNyRWHxtBBG5R7IheHZIUM4WwPB2oqzDpECGNbA2iGCTvyZ_aHOdG5LwotP6WTe9YT6gCFmcO3Y8\" alt=\"\" style=\"width:209px;height:131px\"\/><\/figure><\/div>\n\n\n<p class=\"has-text-align-center has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Solu\u00e7\u00e3o:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Aplicando a rela\u00e7\u00e3o cateto\/hipotenusa\/proje\u00e7\u00e3o, teremos:<\/p>\n\n\n\n<p class=\"has-medium-font-size\">No tri\u00e2ngulo a hipotenusa mede 14 (5+9) e as proje\u00e7\u00f5es medem 5 e 9, ent\u00e3o<\/p>\n\n\n\n<p class=\"has-medium-font-size\">c<sup>2<\/sup> = a.m&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">c<sup>2<\/sup> = 14.5<\/p>\n\n\n\n<p class=\"has-medium-font-size\">c<sup>2<\/sup> = 70 (Extraindo a raiz quadrada)<\/p>\n\n\n\n<p class=\"has-medium-font-size\">c \u2243 8,4&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">b<sup>2<\/sup> = a.n<\/p>\n\n\n\n<p class=\"has-medium-font-size\">b<sup>2<\/sup> = 14.9<\/p>\n\n\n\n<p class=\"has-medium-font-size\">b<sup>2<\/sup> = 126 (Extraindo a raiz quadrada)<\/p>\n\n\n\n<p class=\"has-medium-font-size\"> b \u2243 11,2<\/p>\n\n\n\n<p class=\"has-medium-font-size\">O s\u00edmbolo \u2243 quer dizer que o valor \u00e9 aproximado.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Ficamos por aqui, at\u00e9 o pr\u00f3ximo<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Atividade<\/strong><\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 01<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Em um tri\u00e2ngulo ret\u00e2ngulo <strong>XYZ<\/strong>, as proje\u00e7\u00f5es ortogonais dos catetos sobre a hipotenusa <strong>YZ<\/strong> s\u00e3o <strong>YH<\/strong> e <strong>HZ<\/strong>. Se a proje\u00e7\u00e3o <strong>YH<\/strong> sobre a hipotenusa mede 5 cm e a proje\u00e7\u00e3o <strong>HZ<\/strong> sobre a hipotenusa mede 8 cm, calcule a altura do tri\u00e2ngulo a partir dessas medidas.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/N5g2JygwoYMP-cR67D_tppVHPJwBHAIw6J_mxIzOX2z9l8sY02awUFA85DIF3khmllu3oUzdCdm1Nd1iSxbv01rqlfzxwEL_bJnZNKTfSXbmUYOS0sXQOG7IiPTir36mFuK65Sn7Q74Y\" alt=\"\" style=\"width:217px;height:119px\"\/><\/figure><\/div>\n\n\n<p class=\"has-text-align-center has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 02<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">No tri\u00e2ngulo ret\u00e2ngulo <strong><em>ABC<\/em><\/strong><em> <\/em>abaixo, <strong><em>BC<\/em><\/strong> representa a hipotenusa, <strong>A<em>B<\/em><\/strong><em> e <\/em><strong><em>AC<\/em><\/strong><em> s\u00e3o os catetos<\/em> e <strong>BD <\/strong>e <strong>DC<\/strong> as proje\u00e7\u00f5es ortogonais dos catetos. Determinar as medidas do cateto <strong>AB<\/strong> (b) e da proje\u00e7\u00e3o <strong>DC<\/strong> (n).<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh7-us.googleusercontent.com\/dDpOq-VDH0v0ZuriJd19_aX_UDvAgxFTf1sTD9Qs8SeyLtqkwZlMHlpvEOsp-WZlypER6bJbjHHqj1qGGlZtHHvokZPJsL_h8VlZBah14jEvCObtVInmQCU8dqOkf5kLg5pm1XGJWxb8\" alt=\"\" style=\"width:230px;height:143px\"\/><\/figure><\/div>\n\n\n<p class=\"has-text-align-center has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 03<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">No tri\u00e2ngulo ret\u00e2ngulo <strong>PQR<\/strong>, podemos afirmar que os catetos, <strong>b<\/strong> e <strong>c<\/strong>, medem, aproximadamente<\/p>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:25% auto\"><figure class=\"wp-block-media-text__media\"><img decoding=\"async\" width=\"264\" height=\"148\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/11\/xx.png\" alt=\"\" class=\"wp-image-173351 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-medium-font-size\">(A) 6,3 e 7,7<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(B) 7,7 e 6,3<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(C) 5,3 e 6,3<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(D) 6,3 e 5,3<\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-text-align-left has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 04<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">No tri\u00e2ngulo ret\u00e2ngulo <strong>MNO<\/strong>, se a hipotenusa, <strong>NO<\/strong>, mede 24, ent\u00e3o, podemos afirmar que a proje\u00e7\u00e3o <strong>m<\/strong> do cateto <strong>MO<\/strong>, mede<\/p>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:25% auto\"><figure class=\"wp-block-media-text__media\"><img decoding=\"async\" width=\"248\" height=\"148\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/11\/xy.png\" alt=\"\" class=\"wp-image-173352 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-medium-font-size\">(A) 14<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(B) 16<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(C) 18<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(D) 20<\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-small-font-size\">Imagem do autor produzida no Geogebra<\/p>\n\n\n\n<figure class=\"wp-block-table is-style-stripes\"><table><tbody><tr><td>Autoria<\/td><td>Professor H\u00e9lio Roberto da Rocha, Mestre em Matem\u00e1tica<\/td><\/tr><tr><td>Componente Curricular:<\/td><td>Matem\u00e1tica<\/td><\/tr><tr><td>Objetivos de Aprendizagem e Desenvolvimento:<\/td><td>(EJAMA0620) Interpretar, resolver e elaborar situa\u00e7\u00f5es-problema envolvendo rela\u00e7\u00f5es m\u00e9tricas no tri\u00e2ngulo ret\u00e2ngulo e as rela\u00e7\u00f5es de proporcionalidade nas retas paralelas cortadas por secantes.<\/td><\/tr><tr><td>Refer\u00eancias<\/td><td>SOUZA, Joamir Roberto de: Matem\u00e1tica realidade &amp; tecnologia: 9\u00ba ano: ensino fundamental: anos finais \/ Joamir Roberto de Souza. \u2013 1. ed. \u2013 S\u00e3o Paulo: FTD, 2018.<br>GIOVANNI J\u00daNIOR, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 9\u00b0 ano: ensino fundamental: anos finais \/ Jos\u00e9 Ruy Giovanni J\u00fanior, Benedicto Castrucci. \u2014 4. ed. \u2014 S\u00e3o Paulo: FTD, 2018.<br>PATARO, Patricia Moreno Matem\u00e1tica essencial 9\u00b0 ano: ensino fundamental, anos finais \/ Patricia Moreno Pataro, Rodrigo Balestri. &#8211; 1. ed. &#8211; S\u00e3o Paulo: Scipione, 2018.<br><\/td><\/tr><\/tbody><\/table><\/figure>\n","protected":false},"author":47,"featured_media":173349,"template":"","meta":{"_acf_changed":false,"ocean_post_layout":"","ocean_both_sidebars_style":"","ocean_both_sidebars_content_width":0,"ocean_both_sidebars_sidebars_width":0,"ocean_sidebar":"","ocean_second_sidebar":"","ocean_disable_margins":"enable","ocean_add_body_class":"","ocean_shortcode_before_top_bar":"","ocean_shortcode_after_top_bar":"","ocean_shortcode_before_header":"","ocean_shortcode_after_header":"","ocean_has_shortcode":"","ocean_shortcode_after_title":"","ocean_shortcode_before_footer_widgets":"","ocean_shortcode_after_footer_widgets":"","ocean_shortcode_before_footer_bottom":"","ocean_shortcode_after_footer_bottom":"","ocean_display_top_bar":"default","ocean_display_header":"default","ocean_header_style":"","ocean_center_header_left_menu":"","ocean_custom_header_template":"","ocean_custom_logo":0,"ocean_custom_retina_logo":0,"ocean_custom_logo_max_width":0,"ocean_custom_logo_tablet_max_width":0,"ocean_custom_logo_mobile_max_width":0,"ocean_custom_logo_max_height":0,"ocean_custom_logo_tablet_max_height":0,"ocean_custom_logo_mobile_max_height":0,"ocean_header_custom_menu":"","ocean_menu_typo_font_family":"","ocean_menu_typo_font_subset":"","ocean_menu_typo_font_size":0,"ocean_menu_typo_font_size_tablet":0,"ocean_menu_typo_font_size_mobile":0,"ocean_menu_typo_font_size_unit":"px","ocean_menu_typo_font_weight":"","ocean_menu_typo_font_weight_tablet":"","ocean_menu_typo_font_weight_mobile":"","ocean_menu_typo_transform":"","ocean_menu_typo_transform_tablet":"","ocean_menu_typo_transform_mobile":"","ocean_menu_typo_line_height":0,"ocean_menu_typo_line_height_tablet":0,"ocean_menu_typo_line_height_mobile":0,"ocean_menu_typo_line_height_unit":"","ocean_menu_typo_spacing":0,"ocean_menu_typo_spacing_tablet":0,"ocean_menu_typo_spacing_mobile":0,"ocean_menu_typo_spacing_unit":"","ocean_menu_link_color":"","ocean_menu_link_color_hover":"","ocean_menu_link_color_active":"","ocean_menu_link_background":"","ocean_menu_link_hover_background":"","ocean_menu_link_active_background":"","ocean_menu_social_links_bg":"","ocean_menu_social_hover_links_bg":"","ocean_menu_social_links_color":"","ocean_menu_social_hover_links_color":"","ocean_disable_title":"default","ocean_disable_heading":"default","ocean_post_title":"","ocean_post_subheading":"","ocean_post_title_style":"","ocean_post_title_background_color":"","ocean_post_title_background":0,"ocean_post_title_bg_image_position":"","ocean_post_title_bg_image_attachment":"","ocean_post_title_bg_image_repeat":"","ocean_post_title_bg_image_size":"","ocean_post_title_height":0,"ocean_post_title_bg_overlay":0.5,"ocean_post_title_bg_overlay_color":"","ocean_disable_breadcrumbs":"default","ocean_breadcrumbs_color":"","ocean_breadcrumbs_separator_color":"","ocean_breadcrumbs_links_color":"","ocean_breadcrumbs_links_hover_color":"","ocean_display_footer_widgets":"default","ocean_display_footer_bottom":"default","ocean_custom_footer_template":""},"eaja_categoria":[69],"serie":[100],"eaja_componente":[78],"class_list":["post-173347","eaja","type-eaja","status-publish","has-post-thumbnail","hentry","eaja_categoria-2o-segmento-7a-e-8a-serie","serie-8a-serie","eaja_componente-matematica","entry","has-media"],"acf":[],"_links":{"self":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja\/173347","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja"}],"about":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/types\/eaja"}],"author":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/users\/47"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media\/173349"}],"wp:attachment":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media?parent=173347"}],"wp:term":[{"taxonomy":"eaja_categoria","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_categoria?post=173347"},{"taxonomy":"serie","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/serie?post=173347"},{"taxonomy":"eaja_componente","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_componente?post=173347"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}