{"id":164891,"date":"2023-06-16T15:43:50","date_gmt":"2023-06-16T18:43:50","guid":{"rendered":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/?post_type=eaja&#038;p=164891"},"modified":"2024-03-29T17:33:55","modified_gmt":"2024-03-29T20:33:55","slug":"matematica-soma-e-produto-das-raizes-da-equacao-do-2-grau","status":"publish","type":"eaja","link":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/eaja\/matematica-soma-e-produto-das-raizes-da-equacao-do-2-grau\/","title":{"rendered":"Matem\u00e1tica &#8211; Soma e produto das ra\u00edzes da equa\u00e7\u00e3o do 2\u00b0 grau"},"content":{"rendered":"\n<p class=\"has-text-align-center has-medium-font-size\"><strong>Esta proposta de atividade de Matem\u00e1tica \u00e9 destinada aos estudantes do 6\u00ba Per\u00edodo (8\u00aa s\u00e9rie)&nbsp;da Educa\u00e7\u00e3o de Jovens e Adultos \u2013 EJA.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-buttons has-custom-font-size has-medium-font-size is-content-justification-center is-layout-flex wp-container-core-buttons-is-layout-16018d1d wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button has-custom-font-size has-medium-font-size\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=1D-byZqvOLAZmwue_5_6IklFXp-8IyOfn\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE A ATIVIDADE<\/a><\/div>\n\n\n\n<div class=\"wp-block-button has-custom-font-size has-medium-font-size\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=12sHWDWF_HIvMVboamqScEJQCoswFSPCA\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE OS SLIDES<\/a><\/div>\n\n\n\n<div class=\"wp-block-button has-custom-font-size has-medium-font-size\"><a class=\"wp-block-button__link wp-element-button\" href=\"https:\/\/drive.google.com\/uc?export=douwnload&amp;id=1UJd6K4iWYhUusxZjrrWRPEEceBFv1Fh-\" target=\"_blank\" rel=\"noreferrer noopener\">BAIXE O TEXTO<\/a><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-media-text is-stacked-on-mobile\" style=\"grid-template-columns:40% auto\"><figure class=\"wp-block-media-text__media\"><img decoding=\"async\" width=\"167\" height=\"104\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/08\/2.png\" alt=\"\" class=\"wp-image-166500 size-full\"\/><\/figure><div class=\"wp-block-media-text__content\">\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#258527\"><strong>O que s\u00e3o equa\u00e7\u00f5es?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Uma equa\u00e7\u00e3o \u00e9 uma <strong>igualdade<\/strong> entre duas senten\u00e7as matem\u00e1ticas contendo uma ou mais inc\u00f3gnitas, representadas geralmente por letras. Elas podem ser resolvidas por meio de opera\u00e7\u00f5es matem\u00e1ticas onde se procura determinar os valores que tornam a senten\u00e7a verdadeira.<\/p>\n\n\n\n<p class=\"has-small-font-size\">Imagem: canva.com\/equa\u00e7\u00e3o<\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#258527\"><strong>Qual a defini\u00e7\u00e3o de equa\u00e7\u00e3o do 2\u00ba grau?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">S\u00e3o todas as equa\u00e7\u00f5es alg\u00e9bricas que envolvem uma vari\u00e1vel elevada ao quadrado (2\u00ba grau), como por exemplo:&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" width=\"161\" height=\"35\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-83.png\" alt=\"\" class=\"wp-image-164897\"\/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Onde: <\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\"><strong>a<\/strong>, <strong>b<\/strong> e <strong>c<\/strong> s\u00e3o n\u00fameros reais, com <strong>a<\/strong> diferente de zero, chamados de <strong>coeficientes<\/strong>;<\/li>\n\n\n\n<li class=\"has-medium-font-size\"><strong>x<\/strong> \u00e9 a vari\u00e1vel que queremos encontrar.<\/li>\n<\/ul>\n\n\n\n<p class=\"has-medium-font-size\">O objetivo \u00e9 encontrar os <strong>valores de x que satisfazem a equa\u00e7\u00e3o<\/strong>, ou seja, encontrar as <strong>ra\u00edzes da equa\u00e7\u00e3o.<\/strong><\/p>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#258527\"><strong>Quais s\u00e3o os m\u00e9todos para resolver uma equa\u00e7\u00e3o do 2\u00ba grau?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Alguns deles:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\">F\u00f3rmula de Bhaskara.<\/li>\n\n\n\n<li class=\"has-medium-font-size\">Soma e produto das ra\u00edzes.<\/li>\n\n\n\n<li class=\"has-medium-font-size\">Completando quadrado.<\/li>\n\n\n\n<li class=\"has-medium-font-size\">Fatora\u00e7\u00e3o.<\/li>\n<\/ul>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Neste texto iremos abordar a soma e o produto das ra\u00edzes.<\/strong><\/p>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#258527\"><strong>Soma e Produto das ra\u00edzes da equa\u00e7\u00e3o do 2\u00ba grau.<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Considerando uma equa\u00e7\u00e3o do 2\u00ba grau na forma <strong>ax\u00b2 + bx + c = 0<\/strong>, cujas ra\u00edzes s\u00e3o representadas por <strong>x\u2081<\/strong> e <strong>x\u2082<\/strong>, teremos:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\">a soma das ra\u00edzes (S):<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" width=\"217\" height=\"37\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-84.png\" alt=\"\" class=\"wp-image-164898\"\/><\/figure>\n\n\n\n<ul class=\"wp-block-list\">\n<li class=\"has-medium-font-size\">o produto das ra\u00edzes (P):<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"396\" height=\"50\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-85.png\" alt=\"\" class=\"wp-image-164899\" srcset=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-85.png 396w, https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-85-300x38.png 300w\" sizes=\"(max-width: 396px) 100vw, 396px\" \/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Dividindo a equa\u00e7\u00e3o ax\u00b2 + bx + c = 0 por <strong>a<\/strong>, obtemos:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"174\" height=\"44\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-86.png\" alt=\"\" class=\"wp-image-164900\"\/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Substituindo os valores S e P, podemos reescrever a equa\u00e7\u00e3o ax\u00b2 + bx + c = 0 utilizando a soma (S) e o produto (P) das ra\u00edzes como:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"32\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-87.png\" alt=\"\" class=\"wp-image-164902\"\/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Veja o v\u00eddeo abaixo com essa explica\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"has-text-color has-medium-font-size\" style=\"color:#258527\"><strong>Mas como utilizar esse m\u00e9todo para resolver uma equa\u00e7\u00e3o?<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Segue 3 exemplos.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Exemplo 1<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Determinar a solu\u00e7\u00e3o da equa\u00e7\u00e3o<\/strong> <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"30\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-88.png\" alt=\"\" class=\"wp-image-164903\"\/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Vamos comparar essa equa\u00e7\u00e3o com aquela que aparece a soma e o produto.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"30\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-88.png\" alt=\"\" class=\"wp-image-164903\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"32\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-87.png\" alt=\"\" class=\"wp-image-164902\"\/><\/figure>\n\n\n\n<p class=\"has-black-color has-text-color has-medium-font-size\">Podemos ver, facilmente, que a soma das ra\u00edzes \u00e9 igual a 5 e o produto \u00e9 igual a 6.<\/p>\n\n\n\n<p class=\"has-black-color has-text-color has-medium-font-size\">Os dois n\u00fameros cuja soma \u00e9 5 e produto 6 s\u00e3o as ra\u00edzes dessa equa\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"has-black-color has-text-color has-medium-font-size\">Esses n\u00fameros s\u00e3o o 2 e o 3 pois 2+3=5 e 2.3=6, logo a solu\u00e7\u00e3o da equa\u00e7\u00e3o ser\u00e1 S={2,3}.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Exemplo 2:<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Determinar o conjunto solu\u00e7\u00e3o da equa\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"170\" height=\"28\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-89.png\" alt=\"\" class=\"wp-image-164910\"\/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Neste exemplo vamos determinar a soma e o produto atrav\u00e9s das suas f\u00f3rmulas.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Os coeficientes da equa\u00e7\u00e3o s\u00e3o: a = 1, b = -3 e c = -10.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Substituindo esses valores nas f\u00f3rmulas, obtemos os valores de S e P.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">S = -b\/a = -(-3)\/1 = 3<\/p>\n\n\n\n<p class=\"has-medium-font-size\">P = c\/a = -10\/1 = -10<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Temos que determinar 2 n\u00fameros cuja soma seja igual a 3 e cujo produto seja igual a -10.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Facilmente verificamos que esses n\u00fameros s\u00e3o o &#8211; 2 e 5 pois, -2+5=3 e (-2).5=-10.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Portanto, a solu\u00e7\u00e3o da equa\u00e7\u00e3o \u00e9 igual a S={-2,5}.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Exemplo 3<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Fa\u00e7a o mesmo para a equa\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"159\" height=\"31\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-90.png\" alt=\"\" class=\"wp-image-164911\"\/><\/figure>\n\n\n\n<p class=\"has-medium-font-size\">Observe que o valor do coeficiente <strong>a<\/strong> \u00e9 2 (diferente de 1) ent\u00e3o a soma e o produto podem ser n\u00fameros fracion\u00e1rios, neste caso sim. Veja:<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Soma das ra\u00edzes (S) = -b\/a = -7\/2&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Produto das ra\u00edzes (P) = c\/a = 3\/2<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Agora percebe que fica bem mais complicado determinar as ra\u00edzes?<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Melhor partir para outro m\u00e9todo.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">No saiba mais temos v\u00eddeo explicando.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">Ficamos por aqui, at\u00e9 o pr\u00f3ximo.<\/p>\n\n\n\n<p class=\"has-medium-font-size\"><strong>Atividade<\/strong><\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 01<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">A equa\u00e7\u00e3o do 2\u00ba grau que tem o produto das ra\u00edzes igual a -8 e a soma igual a 4 \u00e9 dada por:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"186\" height=\"152\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-95.png\" alt=\"\" class=\"wp-image-164921\"\/><\/figure>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 02<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Determine a soma e o produto das ra\u00edzes da equa\u00e7\u00e3o do 2\u00b0 grau abaixo.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"164\" height=\"34\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-94.png\" alt=\"\" class=\"wp-image-164920\"\/><\/figure>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 03<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Um agricultor est\u00e1 planejando construir um campo de futebol retangular em um terreno dispon\u00edvel. Se a largura do campo \u00e9 metade do comprimento e a \u00e1rea total do campo \u00e9 de 450 metros quadrados, podemos afirmar que o campo possui<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(A) 30 m de comprimento e 15m de largura.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(B) 25m de comprimento e 20m de largura.<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(C) 20m de comprimento e 10m de largura.&nbsp;<\/p>\n\n\n\n<p class=\"has-medium-font-size\">(D) 15m de comprimento e 7,5m de largura.<\/p>\n\n\n\n<p class=\"has-light-green-cyan-background-color has-background has-medium-font-size\"><strong>QUEST\u00c3O 04<\/strong><\/p>\n\n\n\n<p class=\"has-medium-font-size\">Considere a equa\u00e7\u00e3o do segundo grau abaixo. Calcule as ra\u00edzes dessa equa\u00e7\u00e3o utilizando a soma e o produto das ra\u00edzes.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"152\" height=\"33\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-93.png\" alt=\"\" class=\"wp-image-164919\" srcset=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-93.png 152w, https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2023\/06\/image-93-150x33.png 150w\" sizes=\"(max-width: 152px) 100vw, 152px\" \/><\/figure>\n\n\n\n<p class=\"has-vivid-green-cyan-background-color has-background has-medium-font-size\"><strong>SAIBA MAIS<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<p class=\"responsive-video-wrap clr\"><iframe title=\"#1 Equa\u00e7\u00f5es de 2\u00ba Grau Completa\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/MMtVtmOOWcU?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe><\/p>\n<\/div><figcaption class=\"wp-element-caption\">Canal do Prof. Helio &lt;YouTube&gt;<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-table is-style-stripes\"><table><tbody><tr><td>Autoria<\/td><td>Professor H\u00e9lio Roberto da Rocha, Mestre em Matem\u00e1tica<\/td><\/tr><tr><td>Componente Curricular:<\/td><td>Matem\u00e1tica<\/td><\/tr><tr><td>Objetivos de Aprendizagem e Desenvolvimento:<\/td><td>(EJAMA0611) Investigar, por meio de poss\u00edveis ra\u00edzes inteiras com soma S e produto P, as solu\u00e7\u00f5es de equa\u00e7\u00f5es do 2\u00b0 grau que podem ser comparadas \u00e0 forma x\u00b2 &#8211; Sx + P = 0.<\/td><\/tr><tr><td>Refer\u00eancias<\/td><td>SOUZA, Joamir Roberto de: Matem\u00e1tica realidade &amp; tecnologia: 9\u00ba ano: ensino fundamental: anos finais \/ Joamir Roberto de Souza. \u2013 1. ed. \u2013 S\u00e3o Paulo: FTD, 2018.<\/td><\/tr><\/tbody><\/table><\/figure>\n","protected":false},"author":47,"featured_media":164893,"template":"","meta":{"_acf_changed":false,"ocean_post_layout":"","ocean_both_sidebars_style":"","ocean_both_sidebars_content_width":0,"ocean_both_sidebars_sidebars_width":0,"ocean_sidebar":"","ocean_second_sidebar":"","ocean_disable_margins":"enable","ocean_add_body_class":"","ocean_shortcode_before_top_bar":"","ocean_shortcode_after_top_bar":"","ocean_shortcode_before_header":"","ocean_shortcode_after_header":"","ocean_has_shortcode":"","ocean_shortcode_after_title":"","ocean_shortcode_before_footer_widgets":"","ocean_shortcode_after_footer_widgets":"","ocean_shortcode_before_footer_bottom":"","ocean_shortcode_after_footer_bottom":"","ocean_display_top_bar":"default","ocean_display_header":"default","ocean_header_style":"","ocean_center_header_left_menu":"","ocean_custom_header_template":"","ocean_custom_logo":0,"ocean_custom_retina_logo":0,"ocean_custom_logo_max_width":0,"ocean_custom_logo_tablet_max_width":0,"ocean_custom_logo_mobile_max_width":0,"ocean_custom_logo_max_height":0,"ocean_custom_logo_tablet_max_height":0,"ocean_custom_logo_mobile_max_height":0,"ocean_header_custom_menu":"","ocean_menu_typo_font_family":"","ocean_menu_typo_font_subset":"","ocean_menu_typo_font_size":0,"ocean_menu_typo_font_size_tablet":0,"ocean_menu_typo_font_size_mobile":0,"ocean_menu_typo_font_size_unit":"px","ocean_menu_typo_font_weight":"","ocean_menu_typo_font_weight_tablet":"","ocean_menu_typo_font_weight_mobile":"","ocean_menu_typo_transform":"","ocean_menu_typo_transform_tablet":"","ocean_menu_typo_transform_mobile":"","ocean_menu_typo_line_height":0,"ocean_menu_typo_line_height_tablet":0,"ocean_menu_typo_line_height_mobile":0,"ocean_menu_typo_line_height_unit":"","ocean_menu_typo_spacing":0,"ocean_menu_typo_spacing_tablet":0,"ocean_menu_typo_spacing_mobile":0,"ocean_menu_typo_spacing_unit":"","ocean_menu_link_color":"","ocean_menu_link_color_hover":"","ocean_menu_link_color_active":"","ocean_menu_link_background":"","ocean_menu_link_hover_background":"","ocean_menu_link_active_background":"","ocean_menu_social_links_bg":"","ocean_menu_social_hover_links_bg":"","ocean_menu_social_links_color":"","ocean_menu_social_hover_links_color":"","ocean_disable_title":"default","ocean_disable_heading":"default","ocean_post_title":"","ocean_post_subheading":"","ocean_post_title_style":"","ocean_post_title_background_color":"","ocean_post_title_background":0,"ocean_post_title_bg_image_position":"","ocean_post_title_bg_image_attachment":"","ocean_post_title_bg_image_repeat":"","ocean_post_title_bg_image_size":"","ocean_post_title_height":0,"ocean_post_title_bg_overlay":0.5,"ocean_post_title_bg_overlay_color":"","ocean_disable_breadcrumbs":"default","ocean_breadcrumbs_color":"","ocean_breadcrumbs_separator_color":"","ocean_breadcrumbs_links_color":"","ocean_breadcrumbs_links_hover_color":"","ocean_display_footer_widgets":"default","ocean_display_footer_bottom":"default","ocean_custom_footer_template":""},"eaja_categoria":[69],"serie":[100],"eaja_componente":[78],"class_list":["post-164891","eaja","type-eaja","status-publish","has-post-thumbnail","hentry","eaja_categoria-2o-segmento-7a-e-8a-serie","serie-8a-serie","eaja_componente-matematica","entry","has-media"],"acf":[],"_links":{"self":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja\/164891","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja"}],"about":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/types\/eaja"}],"author":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/users\/47"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media\/164893"}],"wp:attachment":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media?parent=164891"}],"wp:term":[{"taxonomy":"eaja_categoria","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_categoria?post=164891"},{"taxonomy":"serie","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/serie?post=164891"},{"taxonomy":"eaja_componente","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_componente?post=164891"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}