{"id":133659,"date":"2021-11-08T09:32:24","date_gmt":"2021-11-08T11:32:24","guid":{"rendered":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/?post_type=eaja&#038;p=133659"},"modified":"2021-12-22T10:37:37","modified_gmt":"2021-12-22T12:37:37","slug":"matematica-area-de-triangulos-e-quadrilateros","status":"publish","type":"eaja","link":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/eaja\/matematica-area-de-triangulos-e-quadrilateros\/","title":{"rendered":"Matem\u00e1tica &#8211; \u00c1rea de tri\u00e2ngulos e quadril\u00e1teros"},"content":{"rendered":"\n<p class=\"has-black-color has-vivid-green-cyan-background-color has-text-color has-background\" style=\"font-size:25px\">Ol\u00e1! Esta aula de&nbsp;<strong>Matem\u00e1tica&nbsp;<\/strong>\u00e9 destinada a estudantes da<strong>&nbsp;6\u00aa S\u00e9rie<\/strong>&nbsp;da Eaja.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img fetchpriority=\"high\" decoding=\"async\" src=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2021\/11\/aaaa-e1636369876884.jpg\" alt=\"\" class=\"wp-image-133661\" width=\"846\" height=\"553\" srcset=\"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2021\/11\/aaaa-e1636369876884.jpg 606w, https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-content\/uploads\/2021\/11\/aaaa-e1636369876884-300x196.jpg 300w\" sizes=\"(max-width: 846px) 100vw, 846px\" \/><figcaption>Dispon\u00edvel em: Simples Apartamento Cores &#8211; Imagens gr\u00e1tis no Pixabay \n\n<\/figcaption><\/figure>\n\n\n\n<p class=\"has-black-color has-cyan-bluish-gray-background-color has-text-color has-background\" style=\"font-size:25px\">Nesta atividade voc\u00ea ir\u00e1 estabelecer express\u00f5es de c\u00e1lculo de \u00e1rea de tri\u00e2ngulos e quadril\u00e1teros, al\u00e9m de resolver problemas de c\u00e1lculos de medida de \u00e1rea de figuras que podem ser decompostas por quadrados, ret\u00e2ngulos e\/ou tri\u00e2ngulos. <\/p>\n\n\n\n<p class=\"has-text-align-center has-black-color has-pale-cyan-blue-background-color has-text-color has-background\" style=\"font-size:25px\">Assista \u00e0 videoaula do professor H\u00e9lio sobre essa tem\u00e1tica.<\/p>\n\n\n\n<figure class=\"wp-block-embed aligncenter is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<p class=\"responsive-video-wrap clr\"><iframe title=\"\u00c1rea de tri\u00e2ngulos e quadril\u00e1teros | Matem\u00e1tica - aula 11 | 6\u00aa s\u00e9rie - Eaja\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/gF-R9Ae-TVA?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture\" allowfullscreen><\/iframe><\/p>\n<\/div><figcaption>\u00c1rea de tri\u00e2ngulos e quadril\u00e1teros | Matem\u00e1tica &#8211; aula 11 | 6\u00aa s\u00e9rie &#8211; Eaja<\/figcaption><\/figure>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\"><strong>\u00c1rea (Defini\u00e7\u00e3o):<\/strong> \u00e9 a medida de uma superf\u00edcie, por exemplo, a \u00e1rea de um campo de futebol \u00e9 a medida do seu gramado. Para se calcular a \u00e1rea de uma superf\u00edcie, de tamanho m\u00e9dio medida em metros, basta quadricular essa superf\u00edcie em quadrados de lado medindo 1 metro. A \u00e1rea ser\u00e1 a quantidade de quadrados de 1 metro de lado. O resultado ser\u00e1 dado em metros quadrados.<\/p>\n\n\n\n<p class=\"has-text-align-center has-black-color has-light-green-cyan-background-color has-text-color has-background\" style=\"font-size:25px\"><strong>\u00c1rea de Ret\u00e2ngulo<\/strong><\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/IC5nK37WpYFeKFXVkw3Nj0r5-gjN6QIHqI0SxHmT092_K5hKl5wp3c-GgWck2EB72lSYKbUTh2_VsuRVlfz-23a9iM8W5wwhXH45GeP--CogS6MxIAHod1S79DceIirwuzqrsH3W2Ji-mo343Q\" alt=\"\"\/><\/figure><\/div>\n\n\n\n<p class=\"has-text-align-center has-light-green-cyan-background-color has-background\" style=\"font-size:25px\"><strong>\u00c1rea de Quadrado<\/strong><\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/eICbFw-eaSzhce3mHDWj43OuMTU7Qo6X2k4iixH3YLMURFzaUtSZ3nJg4HyxMFAAJvx95lPNyDyZvagKKoWCzePUdkbvT8ruUOWx9rMqg7IQRX3YEjg7D4NLwVndQEPmgsKKH1gxPOb8XnT69A\" alt=\"\"\/><\/figure><\/div>\n\n\n\n<p class=\"has-text-align-center has-black-color has-light-green-cyan-background-color has-text-color has-background\" style=\"font-size:25px\"><strong>Equival\u00eancia de \u00c1rea ( Decompondo figuras)<\/strong><\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\"><strong>Exemplo 3<\/strong><\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Uma folha de zinco possui a forma da figura abaixo. Quantos cent\u00edmetros quadrados de \u00e1rea tem essa folha?<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/MrbduwMFZM4YJKnRke6OwDqG9RU7MHQwU8hxskk4GjZbZYvHkDmEWjiNe9x9vqIEZFV_nlXIB2TYi1StBzwuBw_aC6TcA0O3ityt5oBhB_CT3FNqIgcUjzGMKLoeUL6i7CogvtOKSESIiPq-3g\" alt=\"\" width=\"328\" height=\"211\"\/><figcaption><strong>Imagem dispon\u00edvel em: PNLD Giovanni J\u00fanior, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7\u00ba ano p. 261.<\/strong><\/figcaption><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Essa figura n\u00e3o \u00e9 nem um ret\u00e2ngulo e nem um quadrado, conv\u00e9m decomp\u00f4-la em figuras conhecidas. Veja a nova figura.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/PKhozJY63eygVXYC_5xzqaj4sITWfnQoqSkIaQtenbEpz-LTGzyLAyYIElZ5y-4xXAj3Fgn_o00Nd0CvNZ6vB1EIeq1Vz3KLQB1jzEy32BJ7GY8XLUt0-REWlANXy6sMZLTXhVpI1TXeTmiEFQ\" alt=\"\" width=\"334\" height=\"221\"\/><figcaption>Imagem dispon\u00edvel em: PNLD Giovanni J\u00fanior, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7\u00ba ano p. 261.<\/figcaption><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Nela, temos um ret\u00e2ngulo (fig I) e um quadrado (fig II) e a \u00e1rea pode ser dada pela soma da \u00e1rea da fig I com a da fig II.<\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">A fig I = 2 x 6 = 12cm<sup>2<\/sup>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; A fig II = 2 x 2 = 4cm<sup>2 <\/sup>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;A total = 12 + 4 = 16 cm<sup>2<\/sup><\/p>\n\n\n\n<p class=\"has-text-align-center has-black-color has-light-green-cyan-background-color has-text-color has-background\" style=\"font-size:25px\"><strong>\u00c1rea de Paralelogramo<\/strong><\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">O paralelogramo \u00e9 um quadril\u00e1tero, para determinar sua \u00e1rea, basta transform\u00e1-lo em um ret\u00e2ngulo. Veja o exemplo<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/jgx_Vcbc6xlUGmMuadrhWD3W4ovM2BevVWppPmjkZPEM7BWxbrz7q_iUnlbAL6s2tDYu0HNRdGltDiZxm04gFv1ZBhNJTIz8ZCMpxABJkJml-4abHAN1wiN0PRB_6xusv8VruzISrItJEzXcVA\" alt=\"\"\/><figcaption>Imagens dispon\u00edveis em: PNLD Giovanni J\u00fanior, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7\u00ba ano p. 261.<\/figcaption><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">O paralelogramo foi transformado em um ret\u00e2ngulo de base medindo 5,4cm e altura 3,2cm, logo a medida da sua \u00e1rea pode ser dada por:&nbsp;<\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">A = 5,4 x 3,2 = 17,28cm<sup>2<\/sup>.&nbsp;&nbsp;&nbsp;<\/p>\n\n\n\n<p class=\"has-text-align-center has-black-color has-light-green-cyan-background-color has-text-color has-background\" style=\"font-size:25px\"><strong>\u00c1rea de Tri\u00e2gnulo<\/strong><\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Para se determinar a \u00e1re de um tri\u00e2ngulo basta construir um paralelogramo cuja \u00e1rea j\u00e1 sabemos determinar. Veja as figuras.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/39EAi6sv2tl5DRxsyFhmGGIcbIZ-5s53QjlzDko2icVKvxFEdj9Q21C5l2BO_ze-UFu88joShECj-Bc4zKK6YCpisOVdCr4tbRSpbbUrSPpKvSzszSWO5S6aMhUhb46N9unCH1VbjYz_yOn-Cg\" alt=\"\"\/><figcaption> Imagens dispon\u00edveis em: PNLD Giovanni J\u00fanior, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7\u00ba ano p. 262. <\/figcaption><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Nota-se que os tri\u00e2ngulos I e II possuem \u00e1eas equivalentes e, juntos, formam o paralelobramo ABCD. Ent\u00e3o a \u00e1rea do tri\u00e2ngulo ABC \u00e9 a metade da \u00e1rea do paralelogramo ABCD. Logo a express\u00e3o alg\u00e9brica para se determinar a \u00e1rea de um tri\u00e2ngulo \u00e9:<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/SK1yvqpf1X4AXnQE0pdtwrMm0qY3vxulQDlggHNkU696DI1TEdxgKMmioDeJ2jRgv9EpA2bLPValuklgxonsiLsTHqjTkOmtE5OZBDkOBs6Ff3INnL8Kuhrh_6OEP99uzMk-0xqtfUQjMi1nbg\" alt=\"\" width=\"253\" height=\"54\"\/><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\"><strong>Exemplo 5:<\/strong><\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Para compor um vitral, foi recortada uma pe\u00e7a de vidro na forma triangular, veja a figura. Quantos cent\u00edmetros quadrados de vidro possui a pe\u00e7a?<\/p>\n\n\n\n<p class=\"has-text-align-center\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/OLorjR6Idl3EIlqnRCgoLrOCbIK_cn96ucEWii0Ouc1nEFXMhfr7RP_7Gj6t4BMbtz3HAaJJ3RRDIo6Abp6QXHayzLtgjUDr_eGEGe9RT_zCpSkNsJxrqlJBOC43E1-roAGiUmEqcDm7NHQeqQ\" style=\"width: 300px;\"><\/p>\n\n\n\n<p class=\"has-text-align-center\" style=\"font-size:12px\">  Imagens dispon\u00edveis em: PNLD Giovanni J\u00fanior, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7\u00ba ano p. 262. <\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Neste caso basta usar a express\u00e3o da \u00e1rea do tri\u00e2ngulo<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/8gkogkzMTqitTZl_x0V-UzkKav222-aKuFGAqBgX5HLrf9xeQinEefVeLVy4v5zFLaJ6PJHJrSeNrJET4CCTmHND-F1KlY4QsywO16gE1VKyGlO_-n0XogUhkVXZAA14e5vSIevaAkwR6rMaVg\" alt=\"\" width=\"264\" height=\"67\"\/><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">Logo, a pe\u00e7a possui 16,8cm<sup>2<\/sup> de vidro.<\/p>\n\n\n\n<p class=\"has-text-align-center has-black-color has-pale-cyan-blue-background-color has-text-color has-background\" style=\"font-size:25px\"><strong>Problemas propostos<\/strong><\/p>\n\n\n\n<ol class=\"has-black-color has-text-color wp-block-list\" style=\"font-size:25px\"><li>Determinar a medida da \u00e1rea das figuras abaixo.<\/li><\/ol>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/wVCCqd2iFg1KymuVsuIsM6a4LBFWGNDXwl86aeKIOM8wrr4ITjueLFTgfTZ2k8e29tMxHcemepA-13MBSDKVmWIfPQsxWgZttgZA8r-2aDybni50-adF4_CLunMxaIAl2I7WLflY0-aqpXKI4w\" alt=\"\"\/><figcaption>Imagens dispon\u00edveis em: PNLD Giovanni J\u00fanior, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7\u00ba ano. p. 264.<\/figcaption><\/figure><\/div>\n\n\n\n<ol start=\"2\" class=\"has-black-color has-text-color wp-block-list\" style=\"font-size:25px\"><li>Um marceneiro deve fazer uma cruz como a da figura. Quantos metros quadrados de madeira ser\u00e3o necess\u00e1rios para realizar o trabalho?<\/li><\/ol>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/3wzDNF7iK1eU8Zt652FTzFOnoE8ORTTWDDKby19fjTnz9IY0dxxGcIgfynJEGuvMqPxn_msE8OEyQGemr_PfALkDhb4_zB9k6I4wfKeTsD1JK3JwiF0paBGTntC9GS5E6Pb3WwxCb0jRYaKqRw\" alt=\"\" width=\"264\" height=\"221\"\/><figcaption> Imagem dispon\u00edvel em: PNLD Giovanni J\u00fanior, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7\u00ba ano. p. 264. <\/figcaption><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">3. Eduardo precisa cercar, com arame, um terreno de forma retangular. Sem trena para fazer a medi\u00e7\u00e3o, ele cortou uma vara de comprimento igual \u00e0 sua altura (1,80 m) e mediu 55 varas no comprimento e 35 varas na largura do terreno. Qual \u00e9, em metros quadrados, a \u00e1rea desse terreno? <\/p>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">4. Observe as medidas de uma vaga de estacionamento do condom\u00ednio onde Fernanda mora. Sabendo que essa vaga possui formato de paralelogramo, calcule a \u00e1rea ocupada por ela.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/lQblEk8q6nAaRdoURpoi5Bb1vMprloG91HpXFWmdV-Lz27LBSwXkarHQ1MXzxsf4wReFfQcvN5wzFQZjf0Wl5UCpMbes26MBUwCWCLUypB_Wv1EZ2ZY3uvRIfJF39TyBShaGkUG8PwhvGK95EQ\" alt=\"\" width=\"343\" height=\"156\"\/><figcaption>Imagem dispon\u00edvel em: PNLD Souza, Joamir Roberto de: Matem\u00e1tica realidade &amp; tecnologia: 7\u00ba ano, p. 208.<\/figcaption><\/figure><\/div>\n\n\n\n<p class=\"has-black-color has-text-color\" style=\"font-size:25px\">5. Determine a \u00e1rea de um&nbsp;<strong>tri\u00e2ngulo<\/strong>&nbsp;cuja base mede 10 cm e a altura tamb\u00e9m mede 10 cm. <\/p>\n\n\n\n<p class=\"has-black-color has-pale-cyan-blue-background-color has-text-color has-background\" style=\"font-size:25px\">Assista aos v\u00eddeos no canal do Prof. H\u00e9lio para aprender um pouco mais. Link: <a href=\"https:\/\/www.youtube.com\/channel\/UCKmf3-WVHXY61WgWrz-OO4Q\">Professor Helio Roberto da Rocha &#8211; YouTube<\/a>&nbsp;<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td><strong>Objetivos de Aprendizagem e Desenvolvimento:<\/strong><\/td><td>(EAJAMA0630) Estabelecer express\u00f5es de c\u00e1lculo de \u00e1rea de tri\u00e2ngulos e de quadril\u00e1teros.&nbsp;(EAJAMA0631) Resolver e elaborar problemas de c\u00e1lculo de medida de \u00e1rea de figuras planas que podem ser decompostas por quadrados, ret\u00e2ngulos e\/ou tri\u00e2ngulos, utilizando a equival\u00eancia entre \u00e1reas.<\/td><\/tr><tr><td><strong>Refer\u00eancias<\/strong><\/td><td>GIOVANNI J\u00daNIOR, Jos\u00e9 Ruy &#8211; A conquista da matem\u00e1tica: 7o ano: ensino fundamental: anos finais \/ Jos\u00e9 Ruy Giovanni J\u00fanior, Benedicto Castrucci. \u2014 4. ed. \u2014 S\u00e3o Paulo: FTD, 2018.SOUZA, Joamir Roberto de: Matem\u00e1tica realidade &amp; tecnologia: 7\u00ba ano: ensino fundamental: anos finais \/ Joamir Roberto de Souza. \u2013 1. ed. \u2013 S\u00e3o Paulo: FTD, 2018.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"has-text-align-center has-cyan-bluish-gray-background-color has-background\" style=\"font-size:25px\"> Professor, essa aula segue a Matriz Estruturante para a Eaja 2021. Foi elaborada no ano de 2020, com a suspens\u00e3o das aulas presenciais devido a pandemia da Covid-19 e segue as orienta\u00e7\u00f5es de flexibiliza\u00e7\u00e3o curricular para o bi\u00eanio 2020\/2021 (Of\u00edcio Circular 149\/2020 Dirped).  <\/p>\n","protected":false},"author":42,"featured_media":133661,"template":"","meta":{"_acf_changed":false,"ocean_post_layout":"","ocean_both_sidebars_style":"","ocean_both_sidebars_content_width":0,"ocean_both_sidebars_sidebars_width":0,"ocean_sidebar":"","ocean_second_sidebar":"","ocean_disable_margins":"enable","ocean_add_body_class":"","ocean_shortcode_before_top_bar":"","ocean_shortcode_after_top_bar":"","ocean_shortcode_before_header":"","ocean_shortcode_after_header":"","ocean_has_shortcode":"","ocean_shortcode_after_title":"","ocean_shortcode_before_footer_widgets":"","ocean_shortcode_after_footer_widgets":"","ocean_shortcode_before_footer_bottom":"","ocean_shortcode_after_footer_bottom":"","ocean_display_top_bar":"default","ocean_display_header":"default","ocean_header_style":"","ocean_center_header_left_menu":"","ocean_custom_header_template":"","ocean_custom_logo":0,"ocean_custom_retina_logo":0,"ocean_custom_logo_max_width":0,"ocean_custom_logo_tablet_max_width":0,"ocean_custom_logo_mobile_max_width":0,"ocean_custom_logo_max_height":0,"ocean_custom_logo_tablet_max_height":0,"ocean_custom_logo_mobile_max_height":0,"ocean_header_custom_menu":"","ocean_menu_typo_font_family":"","ocean_menu_typo_font_subset":"","ocean_menu_typo_font_size":0,"ocean_menu_typo_font_size_tablet":0,"ocean_menu_typo_font_size_mobile":0,"ocean_menu_typo_font_size_unit":"px","ocean_menu_typo_font_weight":"","ocean_menu_typo_font_weight_tablet":"","ocean_menu_typo_font_weight_mobile":"","ocean_menu_typo_transform":"","ocean_menu_typo_transform_tablet":"","ocean_menu_typo_transform_mobile":"","ocean_menu_typo_line_height":0,"ocean_menu_typo_line_height_tablet":0,"ocean_menu_typo_line_height_mobile":0,"ocean_menu_typo_line_height_unit":"","ocean_menu_typo_spacing":0,"ocean_menu_typo_spacing_tablet":0,"ocean_menu_typo_spacing_mobile":0,"ocean_menu_typo_spacing_unit":"","ocean_menu_link_color":"","ocean_menu_link_color_hover":"","ocean_menu_link_color_active":"","ocean_menu_link_background":"","ocean_menu_link_hover_background":"","ocean_menu_link_active_background":"","ocean_menu_social_links_bg":"","ocean_menu_social_hover_links_bg":"","ocean_menu_social_links_color":"","ocean_menu_social_hover_links_color":"","ocean_disable_title":"default","ocean_disable_heading":"default","ocean_post_title":"","ocean_post_subheading":"","ocean_post_title_style":"","ocean_post_title_background_color":"","ocean_post_title_background":0,"ocean_post_title_bg_image_position":"","ocean_post_title_bg_image_attachment":"","ocean_post_title_bg_image_repeat":"","ocean_post_title_bg_image_size":"","ocean_post_title_height":0,"ocean_post_title_bg_overlay":0.5,"ocean_post_title_bg_overlay_color":"","ocean_disable_breadcrumbs":"default","ocean_breadcrumbs_color":"","ocean_breadcrumbs_separator_color":"","ocean_breadcrumbs_links_color":"","ocean_breadcrumbs_links_hover_color":"","ocean_display_footer_widgets":"default","ocean_display_footer_bottom":"default","ocean_custom_footer_template":""},"eaja_categoria":[104],"serie":[75],"eaja_componente":[78],"class_list":["post-133659","eaja","type-eaja","status-publish","has-post-thumbnail","hentry","eaja_categoria-2o-segmento-5a-e-6a-serie","serie-6a-serie","eaja_componente-matematica","entry","has-media"],"acf":[],"_links":{"self":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja\/133659","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja"}],"about":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/types\/eaja"}],"author":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/users\/42"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media\/133661"}],"wp:attachment":[{"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/media?parent=133659"}],"wp:term":[{"taxonomy":"eaja_categoria","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_categoria?post=133659"},{"taxonomy":"serie","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/serie?post=133659"},{"taxonomy":"eaja_componente","embeddable":true,"href":"https:\/\/sme.goiania.go.gov.br\/conexaoescola\/wp-json\/wp\/v2\/eaja_componente?post=133659"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}